2sinπ/2－2cosπ/3＋tanπ－3tanπ/6忘了怎么做的了……

Sinπ/3Tanπ/3+tanπ/6COSπ/6－Tanπ/4COSπ/2 化简：[sin(﹣α)cos(π－α)]∕[tan(π＋α)sin﹙3π／2＋α)] 化简：[sin（2π－2）cos（π＋x）tan（π－x）]/[cos（π－x）sin（3π－x）sin...化简：[sin（2π－2）cos（π＋x）tan（π－x）]/[cos（π－x）sin（3π－x）sin（－π－x）] cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?. tan(π-α)*sin^2(α+π/2)*cos(2π-α)/cos^3(-α-π)*tan(2π-α) sin^2就是sin的平方,下同 [sin^2(-a)*cos(π+a)]/[tan(2π+a)*tan(π+a)*cos^3(-π-a)]=? sin(2π-α)tan(α+3π)tan(-α-π)/tan(α-3π)cos(π-α) 化简:(sin(α-3π)*cos(-α))/(tan(α-5π)*cos^2(α-5π)*tan(4π-α)) 求值sin(π/2)*sin(π/3)+2cos(-π/2)-根号3*tan(π/3) 化简:cos(2π-α)sin(-π-α)/sin(π/2+α)tan(3π-α) tan(π－α)＝2,求(sinα－2cosα)／(3sinα＋cosα)的值? cos²(-a)-sin(-a)/ tan(2π+a)化简 求证2(cosθ -sinθ )/1+sinθ +cosθ =tan(π/4-θ /2)-tanθ /2 化简:tan(π-a)cos(2π-a)sin(-a+3π/2)/cos(-a-π)sin(-π-a) cos(-a+π)sin(-π-a)分之tan(π-a)cos(2π-a)sin(-a+2分之3π) sin｛π－α｝cos｛2π－α｝tan｛－α＋π｝/sin｛π＋α｝化简 已知tan(α+π/4)=2,求2cosα-sinα/cosα+3sinα 已知tanθ=3,求(3cosθ-5sin^2θcosθ)/sin(π-θ)的值