sin｛π－α｝cos｛2π－α｝tan｛－α＋π｝/sin｛π＋α｝化简

sin｛π－α｝cos｛2π－α｝tan｛－α＋π｝/sin｛π＋α｝化简 tanα=m,则sin(α+3π)+cos(π+α)/sin(－α)-cos(π+α)等于? 化简：[sin(﹣α)cos(π－α)]∕[tan(π＋α)sin﹙3π／2＋α)] 已知tan（π-α）=－2／1,则sinαcosα-2sin^2α= Sinπ/3Tanπ/3+tanπ/6COSπ/6－Tanπ/4COSπ/2 设sin(α+π/2)=－1/4,且tanα＞0,求sinα,cosα和tanα的值 tan(π－α)＝2,求(sinα－2cosα)／(3sinα＋cosα)的值? 化简cos(α -π )tan(α-2π)tan(2π-α)/sin(π+α) cos(π-α)tan(2π-α)tan(π-α)/sin(π+α) 化简 2sinα*cosα*cos(2π-α)+cos(π+2α)*cosα*tanα化简! 化简[sin²(α+π)cos(α+π)]/tan(α+π)cos³(-α-π)tan(-α-2π)化简sin²(α+π)cos(α+π)/tan(α+π)cos³(-α-π)tan(-α-2π) 化简cos(α-π)sin²(α+2π)/tan (α+4π)tan(α+π)cos³(-α-π) 化简:(sin(α-3π)*cos(-α))/(tan(α-5π)*cos^2(α-5π)*tan(4π-α)) sin(2π-α)tan(α+3π)tan(-α-π)/tan(α-3π)cos(π-α) cos^2(π+α)+sin(-α)cos(2π+α)tan(-π-α)今天就要 tan(π-α)*sin^2(α+π/2)*cos(2π-α)/cos^3(-α-π)*tan(2π-α) sin^2就是sin的平方,下同 化简:cos(2π-α)sin(-π-α)/sin(π/2+α)tan(3π-α) sin²(-α)·cos(π+α)/tan(2∏+α)tan(∏+α)cos³(-∏-α)