sin²(-α)·cos(π+α)/tan(2∏+α)tan(∏+α)cos³(-∏-α)

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sin²(-α)·cos(π+α)/tan(2∏+α)tan(∏+α)cos³(-∏-α)sin²(-α)·cos(π+α)/tan(2∏+α)tan(∏+α)cos&#

sin²(-α)·cos(π+α)/tan(2∏+α)tan(∏+α)cos³(-∏-α)
sin²(-α)·cos(π+α)/tan(2∏+α)tan(∏+α)cos³(-∏-α)

sin²(-α)·cos(π+α)/tan(2∏+α)tan(∏+α)cos³(-∏-α)
原式=sin²α·(-cosα)/tanαtanα(-cos³α)
=sin²αcosα/(sin²α/cos²α*cos³α)
=1