已知:F(x)=log(a)[(2-x)/x] (a>1)H(x)=F(x)+1/(x+1)求:满足H[x(x-0.5)]>0.5的x范围急用!

来源:学生作业帮助网 编辑:六六作业网 时间:2024/10/04 18:10:36
已知:F(x)=log(a)[(2-x)/x](a>1)H(x)=F(x)+1/(x+1)求:满足H[x(x-0.5)]>0.5的x范围急用!已知:F(x)=log(a)[(2-x)/x](a>1)H

已知:F(x)=log(a)[(2-x)/x] (a>1)H(x)=F(x)+1/(x+1)求:满足H[x(x-0.5)]>0.5的x范围急用!
已知:F(x)=log(a)[(2-x)/x] (a>1)
H(x)=F(x)+1/(x+1)
求:满足H[x(x-0.5)]>0.5的x范围
急用!

已知:F(x)=log(a)[(2-x)/x] (a>1)H(x)=F(x)+1/(x+1)求:满足H[x(x-0.5)]>0.5的x范围急用!
悲剧帝

F(x)=log(a)[(2-x)/x] (a>1)
H(x)=F(x)+1/(x+1)
求:满足H[x(x-0.5)]>0.5的x范围