lingo求助min=tob+tbc+tac;AM=((300-80)^2+(300-210)^2)^(1/2);OM=(80^2+210^2)^(1/2);AC=(AM^2-R^2)^(1/2);OB=(OM^2-R^2)^(1/2);tob=OB/5;tac=AC/5;R/AM=@cos(AMC);R/OM=@cos(OMB);AO=300^2+300^2;(AM^2+OM^2-AO^2)/(2*AM*OM)=@cos(AMO);BMC=2*@acos(-1)-AMC-OMB-AMO

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 20:01:28
lingo求助min=tob+tbc+tac;AM=((300-80)^2+(300-210)^2)^(1/2);OM=(80^2+210^2)^(1/2);AC=(AM^2-R^2)^(1/2);O

lingo求助min=tob+tbc+tac;AM=((300-80)^2+(300-210)^2)^(1/2);OM=(80^2+210^2)^(1/2);AC=(AM^2-R^2)^(1/2);OB=(OM^2-R^2)^(1/2);tob=OB/5;tac=AC/5;R/AM=@cos(AMC);R/OM=@cos(OMB);AO=300^2+300^2;(AM^2+OM^2-AO^2)/(2*AM*OM)=@cos(AMO);BMC=2*@acos(-1)-AMC-OMB-AMO
lingo求助
min=tob+tbc+tac;
AM=((300-80)^2+(300-210)^2)^(1/2);
OM=(80^2+210^2)^(1/2);
AC=(AM^2-R^2)^(1/2);
OB=(OM^2-R^2)^(1/2);
tob=OB/5;
tac=AC/5;
R/AM=@cos(AMC);
R/OM=@cos(OMB);
AO=300^2+300^2;
(AM^2+OM^2-AO^2)/(2*AM*OM)=@cos(AMO);
BMC=2*@acos(-1)-AMC-OMB-AMO;
BC=R*BMC;
v=5/(1+@exp(10-0.1*R^2));
tbc=BC/v;
R>=10;
R

lingo求助min=tob+tbc+tac;AM=((300-80)^2+(300-210)^2)^(1/2);OM=(80^2+210^2)^(1/2);AC=(AM^2-R^2)^(1/2);OB=(OM^2-R^2)^(1/2);tob=OB/5;tac=AC/5;R/AM=@cos(AMC);R/OM=@cos(OMB);AO=300^2+300^2;(AM^2+OM^2-AO^2)/(2*AM*OM)=@cos(AMO);BMC=2*@acos(-1)-AMC-OMB-AMO
最后一句后面加分号