已知f(X)是R上的奇函数,若将f(X)的图像向右平移一个单位,则得到一个偶函数的图像f(X)=-f(-x),那么平移后的函数是F(X-1)=F[-(X-1)]还是F[-X-1]?为什么?
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已知f(X)是R上的奇函数,若将f(X)的图像向右平移一个单位,则得到一个偶函数的图像f(X)=-f(-x),那么平移后的函数是F(X-1)=F[-(X-1)]还是F[-X-1]?为什么?
已知f(X)是R上的奇函数,若将f(X)的图像向右平移一个单位,则得到一个偶函数的图像
f(X)=-f(-x),那么平移后的函数是F(X-1)=F[-(X-1)]还是F[-X-1]?为什么?
已知f(X)是R上的奇函数,若将f(X)的图像向右平移一个单位,则得到一个偶函数的图像f(X)=-f(-x),那么平移后的函数是F(X-1)=F[-(X-1)]还是F[-X-1]?为什么?
肯定是后者嘛.
你的y=f(x),x∈R,平移后变成y=f(x-1).
这个新函数y=f(x-1)的自变量还是“x”.
而偶函数如你所说,f(x)=-f(-x),
即把“x”→“-x”,故f(x-1)=-f[(-x)-1].
last night to block reporters posing as an interview with Hong Kong and reporters to take the lead hit the fertile age, Baiyun District, decorative furniture factory owner LIU Shu-cheng (see newspaper...
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前者,平移后的新函数为f(x-1),自变量应该是(x-1),即对于每个(x-1)有偶函数性质f(x)=f(-x),所以是前者
F[-(x-1)]