设z=f(x,y)且x=t+sint,y=t^2,f(x,y)可微,则dz/dt设z=f(x,y)且x=t+sint,y=t^2,f(x,y)可微,求dz/dt

设z=f(x,y)且x=t+sint,y=t^2,f(x,y)可微,则dz/dt设z=f(x,y)且x=t+sint,y=t^2,f(x,y)可微,求dz/dt 高数!设z=e^(x-2y),而x=sint,y=t^3,求dz/dt 设z=e^(x-2y),而x=sint,y=t^3,求dz/dt 设z=x^2*y^3;,x=sint,y=e的t次方,求dz/dt 设z=x^2-y^2,x=sint,y=cost,求dz/dt 设z=xy+sint,而x=e^t,y=cost,求导数dz/dt求详细解答 设z=f(x,y) 求曲线的长度s,设曲线方程为：x=e^(-t)cost,y=e^(-t)sint,z=e^(-t) (0 密度为1的螺线,x=cost,y=sint,z=2t(0 Z=e(x-2y) X=sint Y等于T的平方 求dz/dt 设z=f(y,y/x) 且f(x,y)具有二阶连续的偏导数,求 设{x=sint y=cos2t,则dy/dx|t=π/4= 设x=t^2+cost,y=1-sint,求dy/dx 隐函数求导 设f可微,且方程y+z=xf(y^2-z^2)确定了函数z=z(x,y),隐函数求导 设f可微,且方程y+z=xf(y^2-z^2)确定了函数z=z(x,y),计算xδz/δx+zδz/δy x=a(t-sint),y=a(1-cost),请构造关于x,y的二元函数f(x,y),使得f(x,y) 设x,y,z为正数,且xyz(x+y+z)=4,则(x+y)(y+z)的最小值 设z=f(x^2-y^2,e^（xy)),求偏导z/x,偏导z/y 证明：f(x)=x*cos(x)不是周期函数证明：假设y=xcosx是周期函数,因为周期函数有f(x+T)=f(x)xcosx=（x+T)cos(x+T)=xcosx*cosT-xsinx*sinT+Tcosx*cosT-Tsinx*sinT所以cosT=1 T=kπ/2-xsinx*sinT+Tcosx*cosT-Tsinx*sinT=0-xsinx*sinT-Tsinx*si