log(2)5=a,log(2)7=b用ab表示log(35)28
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log(2)5=a,log(2)7=b用ab表示log(35)28log(2)5=a,log(2)7=b用ab表示log(35)28log(2)5=a,log(2)7=b用ab表示log(35)28l
log(2)5=a,log(2)7=b用ab表示log(35)28
log(2)5=a,log(2)7=b用ab表示log(35)28
log(2)5=a,log(2)7=b用ab表示log(35)28
log(35)28
=log2 28/log2 35
=(log2 4+log2 7)/(log2 5+log2 7)
=(2+b)/(a+b)
log(2)5=a,log(2)7=b
a+b=log(2)35
log(35)28=log(2)28/log(2)35
=[log(2)4+log(2)7]/log(2)35
=(2+b)/(a+b)
log(2)5=a,log(2)7=b用ab表示log(35)28
已知log(14)7=a log(14)5=b 用ab表示log(35)70=log(3)4*log(4)8*log(8)m=log(4)2 求m
log(8)a+log(4)b^2=5,log(8)b+log(4)a^2=7,求log(2)ab的值
关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1
关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1
已知log(3)2=a log(5)2=b用ab表示log(30)90
1、若lg2=a,lg3=b,则lg√15=?(用a、b表达)2、若log(15)(5)=m,则log(15)(3)=(用m表示)3、log(2)(3)*log(3)(4)*log(4)(5)*log(5)(6)*log(6)(7)*log(7)(8)=?4、设log(3)(2)=log(2)(3^x),x=?这个对数函数我学的很不好,所以希望过
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log(2)(a)=log(3)(b)=log(5)(c)