等差数列an前N项和为Sn,a7=15,S13=?

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/20 15:19:31
等差数列an前N项和为Sn,a7=15,S13=?等差数列an前N项和为Sn,a7=15,S13=?等差数列an前N项和为Sn,a7=15,S13=?从等差数列的基本性质可知:a1+a13=a2+a1

等差数列an前N项和为Sn,a7=15,S13=?
等差数列an前N项和为Sn,a7=15,S13=?

等差数列an前N项和为Sn,a7=15,S13=?
从等差数列的基本性质可知:
a1+a13=a2+a12=a3+a11=a4+a10= a5+a9=a6+a8=2a7
S13=(a1+a13)+(a2+a12)+(a3+a11)+(a4+a10)+(a5+a9)+(a6+a8)+a7
=2a7+2a7+2a7+2a7+2a7+2a7+a7
=13a7
s13=13a7=13*15=195

s13=(a1/2+a13/2 )乘以13=13a7=195 拓展s2n-1=(2n-1)an 记住好用。

a7=a1+6d
S13=13(a1+a13)/2=13(a1+a1+12d)/2=13(a1+d)=13a7=195

s13=(a1+a13)*13/2
=2a7*13/2
=13a7
=13*15
=195

S13=13(a1+a13)/2
a1+a13=2a1+12d=2a7
S13=13(a7+a7)/2=13×15=195