数列{an} 满足a(n+1)+(-1)^nan=2n-1,{an} 的前6项和为

来源：学生作业帮助网编辑：六六作业网时间：2024/11/06 06:56:45

数列{an}满足a(n+1)+(-1)^nan=2n-1,{an}的前6项和为数列{an}满足a(n+1)+(-1)^nan=2n-1,{an}的前6项和为数列{an}满足a(n+1)+(-1)^na

数列{an} 满足a(n+1)+(-1)^nan=2n-1,{an} 的前6项和为
数列{an} 满足a(n+1)+(-1)^nan=2n-1,{an} 的前6项和为

数列{an} 满足a(n+1)+(-1)^nan=2n-1,{an} 的前6项和为
a2-a1=1,a3+a2=3,a4-a3=5,a5+a4=7,a6-a5=9,
a1+a2+...+a6=a1+(a2+a3)+(a4+a5)+a6=10+a1+a6
将a1-a2=-1,a3+a2=3,a4-a3=5,a5+a4=7,a6-a5=9相加得a1+a6=23,故前6项和为33.

已知数列{an}满足a(n+1)=an+n,a1=1,则an= 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 周期性数列问题i已知数列｛an}满足a(n+1)=2an (0 数列｛an｝满足lim(an+1-an)=a,证明liman/n=a 数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010 已知数列{an}满足a(n+1)=an+lg2,a1=1,求an 数列[An]满足a1=2,a（n+1）=3an-2 求an 已知数列an满足a1=1,a(n+1)=an/(3an+1) 求数列通项公式数列{an)满足an=4a(n-1)+3,a1=0,求数列{an}的通项公式数列｛an｝满足a1=1,an=a(n-1)+1/(n2-n),求数列的通项公式求一道很简单的数列题数列｛a｝满足an=（n^2+n+1)/3求an+1 已知数列an满足:a1=1,an-a(n-1)=n n大于等于2 求an 已知数列{an}满足a1=33,a(n+1)-an=2n,则an/n的最小值已知数列{an}满足a1=33,a（n+1）-an=2n,求an/n的最小值已知数列an满足a1=100,a(n+1)-an=2n,则(an)/n的最小值为已知数列an满足a1=2,an=a(n-1)+2n,（n≥2）,求an 已知数列{an}满足a1=2,a(n+1)-an=a(n+1）*an,则a31=? 数列{An}满足A1=1,A(n+3)=An+3,A（n+2)=An +2