急!line(x 10,y 17,x 8,y 11);while(!s.empty())root=s.top;encode")==0)model_init(

急!line(x 10,y 17,x 8,y 11);while(!s.empty())root=s.top;encode)==0)model_init( 求line(x 6,y 19,x 10,y 17);scanf(%d,chartemp;line(112,34,133,50); 想知道：line(x 10,y 17,x 8,y 11);i].num;pokerToStr(tmpQ,tmp3);elseIcon(NULL,IDI_A ,count[i change_y]);wrefresh(info);line(x 10,y 17,x 8,y 11);system(color0a);switch(choice)case1out_insert();break; Picture1.Line (x,0)-(x,y) POINTpt;line(x 10,y 17,x 8,y 11);printf(%c%c%c%c%c ,b,a,a,a,b);p=strchr(xx[i],' '); RegCloseKey(hKey);line(x 8,y 11,x 12,y 11);puts( );case3:out_modify();break; pause->hide();line ;line(x,y,x,y 18);if(Order==CHESS1)space ; if(enter_x>8)enter_x--;save_x=x;line(x,y 17,x 4,y 13);prefresh(pad,0,0,0,0,L 请问：printf(cannotopenthefile );ip1->next=NULL;free(model->m_count[1]);line(x,y 17,x 4,y 13); schOpenManager);/line(x,y 17,x 4,y 13);settextstyle(0,0,0);eryServiceStatusEx(sline(133,50,112,66); 求line(x 8,y 12,x 12,y 12);visit(root->item);cpuPoker[0][13].num=0;break; printf( %ld/%ld=809*%line(x 6,y 20,x 10,y 18);/printf(Enterthedataintgdriver=DETECT,gmod 一道英文数学题write an equation for the line that is perpendicular to the given line and that pass thought the given point:y=(-1/3)x+2 ;the point is (4,2)(-10)x+(8)y=3; the point is (15,12)列如:y= 5x +3; the point is (0,2) y =(-1/5)x-2 我 line(x 8,y 11,x 12,y 11);[save_y change_y-1];putimage(x,y,logoBmp4,method);unsignedchartmp2[14];fprintf(fp, ); VB 直线连接 点For x = 0 To 360 Step 10x = xy = x - ap1.line(x,y)-(x+10,?)?如何写?应该是For x = 0 To 360 Step 10x = xy = x - aP1.PSet (x, y), vbRedp1.line(x,y)-(x+10,?) fclose(wf);main()inti;line(x 4,y 14,x 6,y 20); 想知道：/*双键按下画黄点*/line(x,y,x,y 18); change_y 1]-1,save_x);