若[x-y+3]+|2x+y|=0,则x+y=?

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若[x-y+3]+|2x+y|=0,则x+y=?若[x-y+3]+|2x+y|=0,则x+y=?若[x-y+3]+|2x+y|=0,则x+y=?(x-y+3)+(2x+y)=0x-y+3+2x+y=0

若[x-y+3]+|2x+y|=0,则x+y=?
若[x-y+3]+|2x+y|=0,则x+y=?

若[x-y+3]+|2x+y|=0,则x+y=?
(x-y+3)+(2x+y)=0
x-y+3+2x+y=0
3x=-3
x=-1
把x=-1代入原式,得
y=0
∴x+y=-1

x+y=1

∵[x-y+3]+|2x+y|=0,此时∵x-y+3和2x+y都为绝对值
∴x-y+3和2x+y的值的绝对值都为正
∴x-y+3=0,2x+y=0
∴x=-1,y=2
∴x+y=-1

(1)若2X+Y>0,则原式为X-Y+3+2X+Y=0,得X=-1,Y>2,
(2)若2X+Y=0,则Y=-2X,解得X=-1,Y=2, x+y=1
(3)若2X+Y<0,则原式为X-Y+3-2X-Y=0,-X-2Y+3=0 即X=-2Y+3,代入条件式中为,
2(-2Y+3)+Y<0, 解得Y>2, X<-1,无解

|x-y+3|+|2x+y|=0,
则 x-y=-3,2x+y=0
得到 x=-1,y=2
得x+y=1