判断y=sin(2x+3π/2)奇偶性

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判断y=sin(2x+3π/2)奇偶性判断y=sin(2x+3π/2)奇偶性判断y=sin(2x+3π/2)奇偶性答:y=sin(2x+3兀/2)y=sin(2x+2兀-1/2*兀)y=sin(2x-

判断y=sin(2x+3π/2)奇偶性
判断y=sin(2x+3π/2)奇偶性

判断y=sin(2x+3π/2)奇偶性
答:y=sin(2x+3兀/2)
y=sin(2x+2兀-1/2*兀)
y=sin(2x-兀/2)
y=-sin(兀/2-2x)
y=-cos(2x)
y=-(cosx)^2+(sinx)^2
所以f(-x)=-(cos-x)^2+(sin-x)^2=-(cosx)^2+(sinx)^2=f(x)
所以原函数为偶函数