lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2 lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2解释下为什么同除以x^2,还有第二步=lim x→∞ (1/x²-1)/(2-3/x^2) 怎么算出来等于-1/
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limx→∞(1-x^2)/(2x^2-3)=limx→∞(1/x²-1)/(2-3/x^2)=-1/2limx→∞(1-x^2)/(2x^2-3)=limx→∞(1/x²-1)/
lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2 lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2解释下为什么同除以x^2,还有第二步=lim x→∞ (1/x²-1)/(2-3/x^2) 怎么算出来等于-1/
lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2
lim x→∞ (1-x^2)/(2x^2-3)
=lim x→∞ (1/x²-1)/(2-3/x^2)
=-1/2
解释下为什么同除以x^2,
还有第二步
=lim x→∞ (1/x²-1)/(2-3/x^2)
怎么算出来等于-1/2的
我想起来怎么算了，我好关闭问题
lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2 lim x→∞ (1-x^2)/(2x^2-3) =lim x→∞ (1/x²-1)/(2-3/x^2) =-1/2解释下为什么同除以x^2,还有第二步=lim x→∞ (1/x²-1)/(2-3/x^2) 怎么算出来等于-1/
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