已知数列{an}满足an+2=an+1+an(n∈N*)若a1=1,a5=8,则a3=
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已知数列{an}满足an+2=an+1+an(n∈N*)若a1=1,a5=8,则a3=已知数列{an}满足an+2=an+1+an(n∈N*)若a1=1,a5=8,则a3=已知数列{an}满足an+2
已知数列{an}满足an+2=an+1+an(n∈N*)若a1=1,a5=8,则a3=
已知数列{an}满足an+2=an+1+an(n∈N*)若a1=1,a5=8,则a3=
已知数列{an}满足an+2=an+1+an(n∈N*)若a1=1,a5=8,则a3=
令a3=x;a4=y;
则x+y=8
(x-1)+x=y
所以x=3,y=5;
a3=3;
递推就行
a3=a2+1,a4=a2+a3=2a2+1,a5=a4+a3=3a2+2
所以a2=2,a3=3
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