2t(3-t)=6怎么解

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2t(3-t)=6怎么解2t(3-t)=6怎么解2t(3-t)=6怎么解t(3-t)=30=3+t^2-3t(t-3/2)^2-9/4+3=0(t-3/2)^2+3/4=0(t-3/2)^2=-3/4

2t(3-t)=6怎么解
2t(3-t)=6怎么解

2t(3-t)=6怎么解
t(3-t)=3
0 = 3 + t^2 - 3t
(t-3/2)^2 - 9/4 + 3 =0
(t-3/2)^2 + 3/4 = 0
(t-3/2)^2 = - 3/4 = (-1) * 3/4 = i^2 * (根号3 /2)^2
t-3/2 = ±根号3 i /2
t= 3/2 ± i(根号3)/2
i是虚数单位.这不是实数解,这方程没有实数解.

约分先,t2-3t+3=0
T2-3t+9/4=-3+9/4
就可以算出来了