数学题!求详细过程!帮忙化简!
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数学题!求详细过程!帮忙化简!数学题!求详细过程!帮忙化简!数学题!求详细过程!帮忙化简!原式=(x-y-x-y)/[(x+y)(x-y)]*(y^2-x^2)/(xy)=(-2y)/(x^2-y^2
数学题!求详细过程!帮忙化简!
数学题!求详细过程!帮忙化简!
数学题!求详细过程!帮忙化简!
原式=(x-y-x-y)/[(x+y)(x-y)] * (y^2-x^2)/(xy)
=(-2y)/(x^2-y^2)*(y^2-x^2)/(xy)
=2y/(xy)
=2/x
原式=(x-y-x-y)/[(x+y)(x-y)] * (y^2-x^2)/(xy)
=(-2y)/(x^2-y^2)*(y^2-x^2)/(xy)
=2y/(xy)
=2/x
[1/(x+y)-1/(x-y)]*(y/x-x/y)
=[(x-y-x-y)/(x+y)(x-y)]/(y²-x²)/xy
=-2y/(x+y)(x-y)*[-(x+y)(x-y)/xy]
=-2/x
原式=[(x-y)-(x+y)]/[(x+y)(x-y)]×(y²-x²)/xy
=-2y/[(x+y)(x-y)]×(y+x)(y-x)/xy
=2/x
原=(x-y-x-y)/[(x+y)(x-y)] * (y^2-x^2)/(xy)
=(-2y)/(x^2-y^2)*(y^2-x^2)/(xy)
=2y/(xy)
=2/x