2x+y/2=5x+2y/4=1,求x+2y+1/2x-3y+7
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2x+y/2=5x+2y/4=1,求x+2y+1/2x-3y+72x+y/2=5x+2y/4=1,求x+2y+1/2x-3y+72x+y/2=5x+2y/4=1,求x+2y+1/2x-3y+7因为2x
2x+y/2=5x+2y/4=1,求x+2y+1/2x-3y+7
2x+y/2=5x+2y/4=1,求x+2y+1/2x-3y+7
2x+y/2=5x+2y/4=1,求x+2y+1/2x-3y+7
因为2x+y/2=5x+2y/4=1
所以:2x+y/2=1
2x+y=2 (1)
5x+2y/4=1
5x+2y=4 (2)
由(1)和(2)建立个方程组并解得:
x=0
y=2
把x=0和y=2代入x+2y+1/2x-3y+7=5/1=5
所以所求代数式的值是5
解方程组得:x=2,y=-3
代入得x+2y+1/2x-3y+7=2-6+1/(4+9+7)=-3/20
5
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