5x∧2-4x-12=0
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5x∧2-4x-12=05x∧2-4x-12=05x∧2-4x-12=0(5x+6)(x-2)
5x∧2-4x-12=0
5x∧2-4x-12=0
5x∧2-4x-12=0
(5x+6)(x-2)
若x∧2+x-1=0则2∧5+2x∧4-x∧3-2x+11=
(-x^4)^2-2(x^2)^3×x×x+(-3x)^3×x^5
用公式法解下列方程,(1)x²+x-12=0 (2)x²-√2x-1/4=0 (3)x²+4x+8=2x﹢11 (4)x(x-4)=2-8x (5)x²+2x=0 (6)x²+2√5x+10=0
(1) √3_____{x|x≤2},(1,2)____{(x,y)|(1) √3_____{x|x≤2},(1,2)____{(x,y)|y=x+1}(2) √2+√5_____{x|x≤2+√3}(3) {x|x/1=x,x∈R}______{x|x的立方-x=0}(4)设U=R,A={x|a≤x≤b}
5x∧2-4x-12=0
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