①(1/2)x2+(1/2)x+1/8=0②(x+1)(x-1)=2√2x③√3x=√2(x+1)(x-1)④2y²-7y+2=0

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①(1/2)x2+(1/2)x+1/8=0②(x+1)(x-1)=2√2x③√3x=√2(x+1)(x-1)④2y²-7y+2=0①(1/2)x2+(1/2)x+1/8=0②(x+1)(x-

①(1/2)x2+(1/2)x+1/8=0②(x+1)(x-1)=2√2x③√3x=√2(x+1)(x-1)④2y²-7y+2=0
①(1/2)x2+(1/2)x+1/8=0②(x+1)(x-1)=2√2x③√3x=√2(x+1)(x-1)④2y²-7y+2=0

①(1/2)x2+(1/2)x+1/8=0②(x+1)(x-1)=2√2x③√3x=√2(x+1)(x-1)④2y²-7y+2=0
①(1/2)x2+(1/2)x+1/8=0
4x²+4x+1=0
(2x+1)²=0
2x+1=0
x=-1/2
②(x+1)(x-1)=2√2x
x²-2√2x-1=0
x=(2√2±2√3)/2
x=√2±√3
③√3x=√2(x+1)(x-1)
√3x=√2x²-√2
√2x²-√3x-√2=0
x=(√3±√11)/2√2
x=(√6±√22)/4
④2y²-7y+2=0
y=(7±√33)/4