1+0.1+2-0.2

X+1/0.2-2X=0.1x+0.2/0.03:X+1/0.2-2X=0.1x+0.2/0.03:X+1/0.2-2X=0.1x+0.2/0.03:(X+1)/0.2-2X=(0.1x+0.2)/0

MATLAB仿真出现错误,A=[-10.8-2.4;3.80.1-0.8;0.12.5-1];AD=[0.20.10.1;-0.30.10.2;0.20.3-0.3];B=[12.2;2.73.5;2

0.2x-0.1/0.3=0.1x+0.2/0.2+10.2x-0.1/0.3=0.1x+0.2/0.2+10.2x-0.1/0.3=0.1x+0.2/0.2+10.2x-0.1/0.3=0.1x+0

1+x/0.1-0.4x-0.5/0.2=1/21+x/0.1-0.4x-0.5/0.2=1/21+x/0.1-0.4x-0.5/0.2=1/210(1+x)-(4x-5)/2=1/220+20x-4

(x+1)/0.3-2x=(0.1x+0.2)/0.05(x+1)/0.3-2x=(0.1x+0.2)/0.05(x+1)/0.3-2x=(0.1x+0.2)/0.05(x+1)/0.3-2x=(0.

0.1X-0.2/0.02-2X+1/0.0.1X-0.2/0.02-2X+1/0.0.1X-0.2/0.02-2X+1/0.(X-0.2)/0.02-(2X+1)/0.2=1去分母:50(X-0.2

(0.1x-0.3)/0.03=(2x+1)/0.2+1.2(0.1x-0.3)/0.03=(2x+1)/0.2+1.2(0.1x-0.3)/0.03=(2x+1)/0.2+1.2100(0.1x-0

0.1x-0.3除以0.03-2x+1除以0.20.1x-0.3除以0.03-2x+1除以0.20.1x-0.3除以0.03-2x+1除以0.20.1x-0.3除以0.03-2x+1除以0.2=(0.

(0.2x+0.1)/0.3-(3x-2)/6=1(0.2x+0.1)/0.3-(3x-2)/6=1(0.2x+0.1)/0.3-(3x-2)/6=1(2x+1)/3-(3x-2)/6=1两边乘以6得

0.1x-0.3除以0.03-2x+1除以0.20.1x-0.3除以0.03-2x+1除以0.20.1x-0.3除以0.03-2x+1除以0.2聊吧乘310(2-0.1x)+150(0.3-x)=32

0.2(x-1)-(-2x-0.1)=1.20.2(x-1)-(-2x-0.1)=1.20.2(x-1)-(-2x-0.1)=1.20.2x-0.2+2x+0.1=1.20.2x+2x=1.2+0.2

0.3x-0.1/0.2-1=0.1x+0.2/0.3x-2/5=2-x+3/2/是分数线0.3x-0.1/0.2-1=0.1x+0.2/0.3x-2/5=2-x+3/2/是分数线0.3x-0.1/0

x+10.1x+0.2_____-2x=_____0.30.05x+10.1x+0.20.30.05x+10.1x+0.2_____-2x=_____0.30.05x+10.1x+0.20.30.05

(1).(0.2x-0.1)(0.1+0.2x)(2).102×98运用平方差公式计算求解答要有过程(1).(0.2x-0.1)(0.1+0.2x)(2).102×98运用平方差公式计算求解答要有过程

0.1x-0.2/0.02-2x+1/0.2=0.5解方程0.1x-0.2/0.02-2x+1/0.2=0.5解方程0.1x-0.2/0.02-2x+1/0.2=0.5解方程解方程：0.1x-0.2/

file11256438924.....file212349...110.10.20.60.2...20.110.30.20.3...30.20.310.20.1.40.60.20.210.3...9

1/20.43/101/50.1=100.20.20.20.20.2=6添加符号或括号,使等式成立1/20.43/101/50.1=100.20.20.20.20.2=6添加符号或括号,使等式成立1/

0.2分之0.1x+0.1-1=3分之2-3x这道题应该怎么算?0.2分之0.1x+0.1-1=3分之2-3x这道题应该怎么算?0.2分之0.1x+0.1-1=3分之2-3x这道题应该怎么算?0.5x

已知二维随机变量(X,Y)的分布率为求E(X)X012Y10.10.20.1Y20.30.10.2已知二维随机变量(X,Y)的分布率为求E(X)X012Y10.10.20.1Y20.30.10.2已知

添上运算符号和括号,使等式成立（1）0.10.20.30.40.5=0（2）0.10.20.30.40.5=1（3）0.10.20.30.40.5=2（4）0.10.20.30.40.5=3（5）0.