∮sin x•cos∧5xdx
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∫sin2x/sin^4x+cos^4xdx?∫sin2x/sin^4x+cos^4xdx?∫sin2x/sin^4x+cos^4xdx?∫sin2x/sin^4x+cos^4xdx=∫sin2x/[
∫sin^3x/cos^4xdx求积分,∫sin^3x/cos^4xdx求积分,∫sin^3x/cos^4xdx求积分,粗略的算了下,答案是1/(3cos^3x)-1/cosx+c做法就是把上面的si
∫sin^4xdx/cos^2x求积分.坐等∫sin^4xdx/cos^2x求积分.坐等∫sin^4xdx/cos^2x求积分.坐等∫sin^4xdx/cos^2x=∫[1-cos²x]
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∫(2+sin²x)/cos²xdx∫(2+sin²x)/cos²xdx∫(2+sin²x)/cos²xdx原式=2∫(secx)^2dx+
数学积分sin^3x/cos^4xdx积分cos^4x/sin^3xdx请详细解答,谢谢!数学积分sin^3x/cos^4xdx积分cos^4x/sin^3xdx请详细解答,谢谢!数学积分sin^3x
∫(cos^2)xdx=∫[1+(cos2x)/2]dx=x/2+(1/4)sin4x+C∫(cos^3)xdx=∫[1-(sin^2)]dsinx=sinx-[(sin^3)x]/3+C以此形式为模
x/sin^xdx求不定积分?x/sin^xdx求不定积分?x/sin^xdx求不定积分?
(xdx)/sin^2x(xdx)/sin^2x(xdx)/sin^2x
∫x/sin^2xdx∫x/sin^2xdx∫x/sin^2xdx原式=∫xcsc^2(x)dx=-∫xd(cotx)=-xcotx+∫cotxdx=-xcotx+∫cosx/sinx*dx=-xco
积分x∧3cos∧3xdx积分x∧3cos∧3xdx积分x∧3cos∧3xdx进行若干次分部积分法,嫌麻烦的话,可用列表法.
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验证该等式是否成立∫cos2xdx=1/2sin2x+C验证该等式是否成立∫cos2xdx=1/2sin2x+C验证该等式是否成立∫cos2xdx=1/2sin2x+C(1/2sin2x+C)''=1/
求微分方程COSxSinydy=COSySinxdx,Y|x=0=π/4的特解求微分方程COSxSinydy=COSySinxdx,Y|x=0=π/4的特解求微分方程COSxSinydy=COSySi
求定积分(x³+sin²x)cos^4xdx范围为(-π/2,π/2)求定积分(x³+sin²x)cos^4xdx范围为(-π/2,π/2)求定积分(x
求不定积分xdx/cos^2x求不定积分xdx/cos^2x求不定积分xdx/cos^2x你要什么网站?
定积分(兀/2到-兀/2)根号cos^3x-cos^5xdx定积分(兀/2到-兀/2)根号cos^3x-cos^5xdx定积分(兀/2到-兀/2)根号cos^3x-cos^5xdx
求不定积分∫xsin3xdx求不定积分∫xsin3xdx求不定积分∫xsin3xdx∫xsin3xdx=-∫x/3dcos3x=-x/3×cos3x+∫cos3xdx/3=-x/3×cos3x+(si
求不定积分∫sin²x/xdx求不定积分∫sin²x/xdx求不定积分∫sin²x/xdx这个函数的原函数是不能用初等函数表达的.我为我的回答负责