Sin(x^-1)求极限
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/22 01:07:39
求极限,limx趋于0x*sin1/x求极限,limx趋于0x*sin1/x求极限,limx趋于0x*sin1/x无穷小与有界函数的乘积,x在x趋于0是是无穷小,而后面那个是有界函数,希望可以帮到你,
求x*sin[2x/(x^2+1)]的极限求x*sin[2x/(x^2+1)]的极限求x*sin[2x/(x^2+1)]的极限x是趋向于什么?不然没法求极限的
求极限lim(x-->0)x^2sin(1/x),求极限lim(x-->0)x^2sin(1/x),求极限lim(x-->0)x^2sin(1/x),没有步骤,结果可直接写0.定理:无穷小与有界函数的
求极限limsin(x^2*sin(1/x))/xx->0求极限limsin(x^2*sin(1/x))/xx->0求极限limsin(x^2*sin(1/x))/xx->0求极限limsin(x^2
limx->1sin(x-1)/x-1求极限limx->1sin(x-1)/x-1求极限limx->1sin(x-1)/x-1求极限1
sin(-x)/1-根号下1-x,求极限,sin(-x)/1-根号下1-x,求极限,sin(-x)/1-根号下1-x,求极限,定义域1≥x,只能是(x→0)limsin(-x)/[1-√(1-x)](
求极限:lim(x*sin(1/x))^2求极限:lim(x*sin(1/x))^2求极限:lim(x*sin(1/x))^2换元,可设t=1/x.易知,当x--->∞时,t---->0且原式=[(s
limx->0(sqrt(sin(1/x^2))求极限limx->0(sqrt(sin(1/x^2))求极限limx->0(sqrt(sin(1/x^2))求极限limx->0(sqrt(sin(1/
求极限ln(1+2x)/sin(1+2x),limx->0求它极限.求极限ln(1+2x)/sin(1+2x),limx->0求它极限.求极限ln(1+2x)/sin(1+2x),limx->0求它极
求极限limx→0(cosx)^1/sin^2x求极限limx→0(cosx)^(1/sin^2x)求极限limx→0(cosx)^1/sin^2x求极限limx→0 (cosx)^(1/s
求极限lim(x→∞)(sin√x+1-sin√x)求极限lim(x→∞)(sin√x+1-sin√x)求极限lim(x→∞)(sin√x+1-sin√x)sina-sinb=2cos[(a+b)/2
求极限lim(x→+∞)(sin√(x+1)-sin√x)求极限lim(x→+∞)(sin√(x+1)-sin√x)求极限lim(x→+∞)(sin√(x+1)-sin√x)sin(A+B)-sin(
求极限sin(x-π/3)/1-cosx在x趋向π/2的极限求极限sin(x-π/3)/1-cosx在x趋向π/2的极限求极限sin(x-π/3)/1-cosx在x趋向π/2的极限代入法求极限结果=0
求极限lim趋近于1sin(πx^a)/sin(πx^b)的值求极限lim趋近于1sin(πx^a)/sin(πx^b)的值求极限lim趋近于1sin(πx^a)/sin(πx^b)的值limx-1/
求[sinln(x+1)-sinlnx的极限,x趋于正无穷求[sinln(x+1)-sinlnx的极限,x趋于正无穷求[sinln(x+1)-sinlnx的极限,x趋于正无穷limsinln(x+1)
求极限lim(x趋向无穷)[(x+1)^(x+1)/x^x]sin(1/x)求极限lim(x趋向无穷)[(x+1)^(x+1)/x^x]sin(1/x)求极限lim(x趋向无穷)[(x+1)^(x+1
求极限((sin(x^3+x^2-x)+sinx)/xx→0已知limsinx/x=1求极限((sin(x^3+x^2-x)+sinx)/xx→0已知limsinx/x=1求极限((sin(x^3+x
函数极限问题当x趋向1时,求[sin^2(x-1)]/(x-1)的极限求详细解释,函数极限问题当x趋向1时,求[sin^2(x-1)]/(x-1)的极限求详细解释,函数极限问题当x趋向1时,求[sin
如何求这个极限?(sin(1/x)+cos(1/x))的x次方当x->无穷时的极限.如何求这个极限?(sin(1/x)+cos(1/x))的x次方当x->无穷时的极限.如何求这个极限?(sin(1/x
求sin(1/x)/1/x当x趋于0的极限是多少即:x*sin(1/x)当x趋于0的极限求sin(1/x)/1/x当x趋于0的极限是多少即:x*sin(1/x)当x趋于0的极限求sin(1/x)/1/