2X+3Y+8Z=100X+Y+Z=20

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/21 23:10:34
X+Y+Z=20,2X+3Y+8Z=100 那么X.Y.Z分别是多少?

X+Y+Z=20,2X+3Y+8Z=100那么X.Y.Z分别是多少?X+Y+Z=20,2X+3Y+8Z=100那么X.Y.Z分别是多少?X+Y+Z=20,2X+3Y+8Z=100那么X.Y.Z分别是多

X+Y+Z=20,2X+3Y+8Z=100 那么X Y Z分别是多少,

X+Y+Z=20,2X+3Y+8Z=100那么XYZ分别是多少,X+Y+Z=20,2X+3Y+8Z=100那么XYZ分别是多少,X+Y+Z=20,2X+3Y+8Z=100那么XYZ分别是多少,如果你限

已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..

已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..已知

X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z

X/10=Y/8=Z/9,则X+Y+Z/2Y-3ZX/10=Y/8=Z/9,则X+Y+Z/2Y-3ZX/10=Y/8=Z/9,则X+Y+Z/2Y-3Z因为X/10=Y/8=Z/9,所以设X=10K,则

已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z

已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z已知

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2

(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?

(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?(4x-2y-z)-{5x-[8

{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2

{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2这个题目没有问题么,

证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0

证明:x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中x,y,z>0证明:x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中x,y,z>0证明:x/(y+z)+y/(z+x)+z

(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊

(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊(4x-2y-z)-{5x-

x/2=y/3=z/5 x+3y-z/x-3y+z

x/2=y/3=z/5x+3y-z/x-3y+zx/2=y/3=z/5x+3y-z/x-3y+zx/2=y/3=z/5x+3y-z/x-3y+z设x/2=y/3=z/5=ax=2ay=3az=5a是不

x+y/2=z+x/3=y+z/4 x+y+z=27

x+y/2=z+x/3=y+z/4x+y+z=27x+y/2=z+x/3=y+z/4x+y+z=27x+y/2=z+x/3=y+z/4x+y+z=27x+y/2=z+x/3=y+z/4①x+y+z=2

若x+y+z=3y=2z,则x/x+y+z=?

若x+y+z=3y=2z,则x/x+y+z=?若x+y+z=3y=2z,则x/x+y+z=?若x+y+z=3y=2z,则x/x+y+z=?x+y+z=3y=2z(x+y+z)/3=y(x+y+z)/2

x+2y=3x+2z=4y+z 求x:y:z

x+2y=3x+2z=4y+z求x:y:zx+2y=3x+2z=4y+z求x:y:zx+2y=3x+2z=4y+z求x:y:zx+2y=3x+2z得y=x+z代入x+2y=4y+z得x+2x+2z=4

(x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z

(x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z(x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z(x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y

3X+2y+z=20 x+y+z=10 Y=3X

3X+2y+z=20x+y+z=10Y=3X3X+2y+z=20x+y+z=10Y=3X3X+2y+z=20x+y+z=10Y=3X3X+2y+z=20(1)x+y+z=10(2)Y=3X(3)(1)

(x+y-z)(x-y+z)=

(x+y-z)(x-y+z)=(x+y-z)(x-y+z)=(x+y-z)(x-y+z)=[x+(z-y)][x-(z-y)]=x-(z-y)记得采纳啊

x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2

x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+