sin(30°+β)-sin(30°-β)化简
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 08:45:15
sin(30°+β)-sin(30°-β)化简sin(30°+β)-sin(30°-β)化简sin(30°+β)-sin(30°-β)化简原式=(sin30cosβ+cos30sinβ)-(sin30
sin(30°+β)-sin(30°-β)化简
sin(30°+β)-sin(30°-β)化简
sin(30°+β)-sin(30°-β)化简
原式=(sin30cosβ+cos30sinβ)-(sin30cosβ-cos30sinβ)
=2cos30sinβ
=√3sinβ
=2cos30sinβ
=√3sinβ
sin(30°+β)-sin(30°-β)化简
计算:sin方10°+sin方20°+sin方30°+sin方40°+sin方50°+sin方60°+sin方70°+sin方80°+sin方90°=
化简sin^(a-30°)+sin^(a+30°)-sin^a化简sin^2(a-30°)+sin^2(a+30°)-sin^2a
求证下列各恒等式:1.sin(30°+α)+cos(60°+α)=cosα1.sin(30°+α)+cos(60°+α)=cosα2.sin(α+β)sin(α-β)=sin²α-sin²β3.cos(α+β)cos(α-β)=cos²β-sin²α
sin(α+30°)-sin(α-30°)/cosα
sin(30°+x)-sin(30°-x)等于多少?
计算:sin²10°+sin²20°+sin²30°+.sin²80°=
计算:sin²10°+sin²20°+sin²30°+……sin²80°=
sin²10°+sin²20°+sin²30°+……+sin²80°=?
证明以下三角等式成立,sin3β*sinγ*sin(60°-γ)/(sin3γ*sinβ*sin(60°-β)) =sin(60°+β)/sin(60证明以下三角等式成立sin3β*sinγ*sin(60°-γ)/(sin3γ*sinβ*sin(60°-β))=sin(60°+β)/sin(60°+γ)
若β=α 30°,则sin²α cos²β sinαcosβ等于若β=α+30°,则sin²α+cos²β+sinαcosβ等于
若β=α 30°,则sin²α cos²β sinαcosβ等于
sin²10°+sin²20°+sin²30°+……+sin²80°+sin²90°=?
诱导公式 200分1.化简:sin(30°+α)×tan(45°+α)×tan(45°-α) sec(60°-α)2.求值:sin²1°+sin²2°+sin²3°+.+sin²89°3.已知θ=(0,2π),且sinθ、COSθ是方程X²-KX+K-1=0的根 求K和θ的值4.已知SINα+SINβ+SINr
已知cos(α+β) =cosαsinβ-sinαsinβ,求sin15°=急阿急阿!
已知sin^2(30°)+sin^2(90°)+sin^2(150°)=1.5sin^2(5°)+sin^2(65°)+sin^2(125°)=1.5 观察两等式 写出一般性命题 并给出证明
化简:sin方(a-30°)+sin方(a+30°)—sin方a
求证:sin^2(α+30°)+sin^2(α-30°)-sin^2α=定值