{x÷7=y÷10=z÷5 ①{x+2y+3z=84 ②
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{x÷7=y÷10=z÷5①{x+2y+3z=84②{x÷7=y÷10=z÷5①{x+2y+3z=84②{x÷7=y÷10=z÷5①{x+2y+3z=84②假设一份东西是k个单位(比如说1本书5克)根
{x÷7=y÷10=z÷5 ①{x+2y+3z=84 ②
{x÷7=y÷10=z÷5 ①
{x+2y+3z=84 ②
{x÷7=y÷10=z÷5 ①{x+2y+3z=84 ②
假设一份东西是k个单位 (比如说1本书5克)
根据 x÷7=y÷10=z÷5 x=7k (也就是说x是7个单位) y=10k z=5k
代入2式得 7k+2×10k+3×5k=84
42k = 84
k=2
x=7×2=14 y=20 z=10
令x/7=y/10=z/5=t,则x=7t,y=10t,z=5t,代入第二个方程可得t=2,
所以x=14,y=20,z=10
{x÷7=y÷10=z÷5 ① {x+2y+3z=84 ②
由 ①得y=2z,x=(7/5)z
带入②得,(7/5)z+2z+3z=84,解得:z=105/8,
带入得:y=105/4,x=147/8
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{x÷7=y÷10=z÷5 ①{x+2y+3z=84 ②
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