lga=2.431 lgb=1.431 则a除以b等于

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lga=2.431lgb=1.431则a除以b等于lga=2.431lgb=1.431则a除以b等于lga=2.431lgb=1.431则a除以b等于lga=2.431,lgb=1.431,a/b=1

lga=2.431 lgb=1.431 则a除以b等于
lga=2.431 lgb=1.431 则a除以b等于

lga=2.431 lgb=1.431 则a除以b等于
lga=2.431,lgb=1.431,
a / b
= 10^2.431 / 10^1.431
= 10^1
= 10

lga/b=lga-lgb=1
所以啊a/b=10

lga/b=lga-lgb=1
故：a/b=10

|lga|=|lgb|,0 lgA+lgB=lgA/B吗?RT lga-lgb=?(lga)/(lgb)=?lg(a/b)=? lga-lgb=lg( a / b)lga+lgb=lg( a X b)lga X lgb=?lga / lgb=? 已知lga+lgb=2,lga*lgb=1/2,则|lga/b|的值为 lga+lgb=2,lga•lgb=1／2,则|lga／b|的值为? 已知lga=2.431,lgb=1.431,则b/a等于 lga=2.431 lgb=1.431 则a除以b等于为什么（lgb/a）²=（lgb+lga）² 证明a^(lgb)=b^(lga) lga+lgb=0 求ab 为什么loga（b）=lgb/lga ? lg（a+b)=lga+lgb?lg（a—b)=lga-lgb?判断题是lg（ab）=lga+lgb还是lg（a+b）=lga·lgb? lgA乘以lgB=lg（A+B）,那么lgA+lgB会不会=lg（AB）设a>1,b>1,若lga+lgb=4,则lga*lgb的最大值是化简lgb/lga+lga/lgb=5/2?麻烦高人了.理解能力一般高中数学求证:a^lgb*b^lga=1还有一个问题：lg(a^lgb)=lga*lgb ?