已知|x+y-1|+√x+2y-3=0,求实数x,y的值
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已知|x+y-1|+√x+2y-3=0,求实数x,y的值已知|x+y-1|+√x+2y-3=0,求实数x,y的值已知|x+y-1|+√x+2y-3=0,求实数x,y的值|x+y-1|+√x+2y-3=
已知|x+y-1|+√x+2y-3=0,求实数x,y的值
已知|x+y-1|+√x+2y-3=0,求实数x,y的值
已知|x+y-1|+√x+2y-3=0,求实数x,y的值
|x+y-1|+√x+2y-3=0
所以x+y-1=0
x+2y-3=0
相减
y-2=0
y=2
x=1-x=-1
x+y-1=0
x+2y-3=0
① -②
-y =-2
y=2
x=-1
|x+y-1|+√x+2y-3=0
所以
|x+y-1|=0,√x+2y-3=0
即
x+y-1=0
x+2y-3=0
相减,得
y-2=0
y=2
所以
x=1-y=1-2=-1
x=-1 y=2
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