设f(x)=(x+1/x)^2 ,x>0.(1) 求函数f(x)的反函数f-1(x)拜托各位了 3Q(2)若x≥2时,不等式(x-1)f-1(x)>a(a-√x)恒成立,求实数a的取值范围

设f(x)={3x-1,x=0,求f(-x),f(x-2). 设f(x-1)={-sinx/x,x>0;2,x=0;x-1,x 设f(x-1)={-sinx/x,x>0;2,x=0;x-1,x 设f(x)=x(x-1)(x-2)...(x-999),则f'(0)=? 设f(x)=x(x-1)(x-2).(x-1000) 则f'(0)=?RT 设f(x)=x(x+1)(x+2).(x+100),则f '(0)= 设f(x)=x/2+1/x(x 设函数f(x)满足f(x)+2f(1/x)=x,求f(x) 设f(x)=1/x(x 设f(x)=1-x,(x 设函数f(x)=x-[x],x≥0,f(x+1),x 设2f(x)+xf(1/x)=(x+2x)/(x+1),求f(x). 设函数f(x)=(x-1)(x-2)...(x-100)(x>100),求F'(X) 设f(x)=ln√x,x>=1,y=f(f(x))设f(x)=ln√x,x>=1, y=f(f(x)),求dy/dx|x=0 2x-1,x 设函数f(x)={x^2+1(x>=0) ,-2x(x 设f (x)={2x+1(x≥0),x²+4(x 设函数f(x)=a/(1+x),x≥0；2x+b,x 设f(x)+f(x-1／x)=2x,求f(x)=?