设y=3^x+cos^5x,求dy需要具体步骤

设y=3^x+cos^5x,求dy需要具体步骤 设y=e^(-x) cos 1/x,求dy. 设y=cos(x^2+e^x)求dy 设函数y=x3 cos x ,求dy 设y=cos^2(x+1),求dy 设y=e^cos^2*1/x,求dy 设y=e^cos^21/x,求dy 设y=e^(-x)cos(3-x),求dy 详细些 设y=cos(2-5x) 则dy=? 设y=cos(5x+4)求y'和dy 等于多少 设y=cos(5x+4)求y'和dy y=e^-x cos 3x,求dy. y=e_x cos x 求dy y=(cos^2x) 求dy 设函数y=e^2x+cos x求倒数y'与微分dy 设e^(x+y)+cos(xy)=0确定y是x的函数求dy 设y等于sion5x+cos立方x求dy 设y=x的5x次方,求dy