已知函数f(x)满足f(cosx)=x/2(0≤x≤π),则f(-1/2)=()A.cos1/2B.π/4C.π/3D.π/2
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 18:12:01
已知函数f(x)满足f(cosx)=x/2(0≤x≤π),则f(-1/2)=()A.cos1/2B.π/4C.π/3D.π/2已知函数f(x)满足f(cosx)=x/2(0≤x≤π),则f(-1/2)
已知函数f(x)满足f(cosx)=x/2(0≤x≤π),则f(-1/2)=()A.cos1/2B.π/4C.π/3D.π/2
已知函数f(x)满足f(cosx)=x/2(0≤x≤π),则f(-1/2)=()
A.cos1/2
B.π/4
C.π/3
D.π/2
已知函数f(x)满足f(cosx)=x/2(0≤x≤π),则f(-1/2)=()A.cos1/2B.π/4C.π/3D.π/2
f(cosx)=x/2(0≤x≤π),
f(-1/2)=f(cos2/3π)=2π/3/2=π/3
选择C
C
C
cosx=-1/2
x=2π/3
f(-1/2)=f(cos2π/3)=2π/3 /2=π/3
已知函数f(x)满足f(cosX)=cos2x,则f(sin165°)=
已知函数f(x)= {cosx (-pai
已知函数f(x)满足f (cosx)=1/2 (x∈[0,π]),则f(-1/2)=?已知函数f(x)满足f (cosx)=1/2(x∈[0,π]),则f(-1/2)=?紧急紧急!
已知定义在R上的函数f(x)满足①:f(x+y)+f(x-y)=2f(x)cosy;②:f(0)=0,f(π/2)=1,求(1)判断f(x)的奇偶性;(2)求f(x)(3)求f(x)+cosx+f(x)cosx(4)求f(x)+cosx+f(x)·cosx的最大值.
已知函数f(x)=sin2x(sinx+cosx)/cosx
已知函数f(x)满足:f(x)-2f(-x)=2x^2-3x+1,则f(x)1.已知f(1+cosx)=cos2x,求f(x)的解析式2.已知函数f(x)满足:f(x)-2f(-x)=2x^2-3x+1,则f(x)
已知一次函数f(x)满足f[f(x)]=4x+3,求f(x)
已知一次函数f(x)满足f[f(x)]=4x-1求f(x)
已知一次函数f(x)满足f[f(x)]=4x+3,求f(x)?
已知函数f(x)满足f(兀+x)=f(兀-x),且当x属于(0,兀)时,f(x)=x+cosx,则f(2),f(3),f(4)的大小关系
已知函数f(x)=x^2-cosx,x∈[-π/2,π/2]时满足f(x)>f(∏/3)的取值范围
已知函数f(x)的定义域为(-2,2),导函数为f'(x)=x^2+2cosx且f(0)=0,则满足f(1+x)+f(x^2-x)>0的实数x的取值范
已知函数f(x)的定义域为(-2,2),导函数为f'(x)=x^2+2cosx且f(0)=0,则满足f(1+x)+f(x^2-x)>0的实数x的取值范
已知函数f(x)=cos2x-(cosx-1)cosx求f(x)最小值
已知函数f(x)=cos2x-(cosx-1)cosx求f(x)最小值
函数f(x)满足f(cosx)=1/2x(0
函数f(x)满足f(cosx)=1/2x(0
已知函数f(x)=1/x cosx,则f(兀)+f'(2/兀)等于多少