y=cos2x在点(x,y)处的切线方程为?(x,y已知)

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y=cos2x在点(x,y)处的切线方程为?(x,y已知)y=cos2x在点(x,y)处的切线方程为?(x,y已知)y=cos2x在点(x,y)处的切线方程为?(x,y已知)y=cos2x在点(x0,

y=cos2x在点(x,y)处的切线方程为?(x,y已知)
y=cos2x在点(x,y)处的切线方程为?(x,y已知)

y=cos2x在点(x,y)处的切线方程为?(x,y已知)
y=cos2x在点(x0,y0)处的切线方程.
1、切点是(x0,y0);
2、切线斜率k=y'|x=x0=[-2sin2x]|x=x0=-2sin(x0)
切线是:
y=(-2sin(x0))(x-x0)+y0