极限基础题 求步骤~~~若lim(an+(n^2+bn-2)/(n-1))=2 则a+b=

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极限基础题求步骤~~~若lim(an+(n^2+bn-2)/(n-1))=2则a+b=极限基础题求步骤~~~若lim(an+(n^2+bn-2)/(n-1))=2则a+b=极限基础题求步骤~~~若li

极限基础题 求步骤~~~若lim(an+(n^2+bn-2)/(n-1))=2 则a+b=
极限基础题 求步骤~~~
若lim(an+(n^2+bn-2)/(n-1))=2 则a+b=

极限基础题 求步骤~~~若lim(an+(n^2+bn-2)/(n-1))=2 则a+b=
请问n是趋向于多少的啊,无穷?还是某个常数?
如果n趋于无穷的话,a=-1,b=1,a+b=0
lim(n趋于无穷)an+((n-1)^2+(b+2)n+b-1)/(n-1)=2
lim(n趋于无穷)an+(n-1)+b+2=2
lim(n趋于无穷)(a+1)n+b+1=2
要使该极限存在,x前的系数为0,所以a=-1,b=1,所以a+b=0