设f(x,y)= e^-sinx (x+2y),fx'(读作f次x)(0,1)=
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设f(x,y)=e^-sinx(x+2y),fx''(读作f次x)(0,1)=设f(x,y)=e^-sinx(x+2y),fx''(读作f次x)(0,1)=设f(x,y)=e^-sinx(x+2y),fx
设f(x,y)= e^-sinx (x+2y),fx'(读作f次x)(0,1)=
设f(x,y)= e^-sinx (x+2y),fx'(读作f次x)(0,1)=
设f(x,y)= e^-sinx (x+2y),fx'(读作f次x)(0,1)=
题意没搞懂 求进一步解释!
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设f(x,y)= e^-sinx (x+2y),fx'(读作f次x)(0,1)=
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