因式分解:X的三次-X的两次-X+1

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/07 16:38:30
因式分解:X的三次-X的两次-X+1因式分解:X的三次-X的两次-X+1因式分解:X的三次-X的两次-X+1X的三次-X的两次-X+1=(x³+1)-(x²+x)=(x+1)(x&

因式分解:X的三次-X的两次-X+1
因式分解:X的三次-X的两次-X+1

因式分解:X的三次-X的两次-X+1
X的三次-X的两次-X+1
=(x³+1)-(x²+x)
=(x+1)(x²-x+1)-x(x+1)
=(x+1)(x²-2x+1)
=(x+1)(x-1)²

X的三次-X的两次-X+1
=x^2(x-1)-(x-1)
=(x-1)(x^2-1)
=(x-1)(x-1)(x+1)
=(x-1)^2(x+1)

X的三次-X的两次-X+1=(x³+1)-x(x+1)=(x+1)(x²-x+1)-x(x+1)=(x+1)(x²-2x+1)=(x+1)(x-1)²

x³-x²-x+1
=x²(x-1)-(x-1)
=(x-1)(x²-1)
=(x-1)(x-1)(x+1)
=(x-1)²(x+1)

首先发现-1是一根(三次因式分解先
验1和-1)然后用那个式子除以(x+1),
得到二次式x^2-2x+1,再分解为(x-1)^2,
所以答案为(x+1)(x-1)^2