求证:多项式(a—2)(a^2+2a+4)—[3a(a+1)^2-2a(a-1)^2-(3a+1)(3a-1)]+a(1+a)的值与a的取值无关

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/18 16:46:37
求证:多项式(a—2)(a^2+2a+4)—[3a(a+1)^2-2a(a-1)^2-(3a+1)(3a-1)]+a(1+a)的值与a的取值无关求证:多项式(a—2)(a^2+2a+4)—[3a(a+

求证:多项式(a—2)(a^2+2a+4)—[3a(a+1)^2-2a(a-1)^2-(3a+1)(3a-1)]+a(1+a)的值与a的取值无关
求证:多项式(a—2)(a^2+2a+4)—[3a(a+1)^2-2a(a-1)^2-(3a+1)(3a-1)]+a(1+a)的值与a的取值无关

求证:多项式(a—2)(a^2+2a+4)—[3a(a+1)^2-2a(a-1)^2-(3a+1)(3a-1)]+a(1+a)的值与a的取值无关
-9