∫1/sin(x/2)dx
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∫1/sin(x/2)dx∫1/sin(x/2)dx∫1/sin(x/2)dx∫1/sin(x/2)dx=2∫csc(x/2)d(x/2)=2∫sin(x/2)/(sin(x/2)^2)d(x/2)=
∫1/sin(x/2)dx
∫1/sin(x/2)dx
∫1/sin(x/2)dx
∫1/sin(x/2)dx
=2∫csc(x/2)d(x/2)
=2∫sin(x/2)/(sin(x/2)^2)d(x/2)
=-2∫dcos(x/2)/(1-(cos(x/2))^2)
=ln|(1-cos(x/2))/(1+cos(x/2))|
=2ln|csc(x/2)-cot(x/2)|+C
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