∫1+sin^2x/1-cos2x dx∫1+sin^2x/1-cos2x dx

∫1+sin^2x/1-cos2x dx∫1+sin^2x/1-cos2x dx 求不定积分 ∫((1+sin^2x)/(1+cos2x))dx ∫（cos2x/cos方x*sin方x）dx∫（1/sin方xcos方x）dx 求不定积分∫(cos2x)/(sin^2x)(cos^2x)dx∫(cos2x)/(sin^2x)(cos^2x)dx ∫（cos2x／sin^2x）dx要有过程 1.∫(2-sec^2(x))*dx 2.∫(cos2x/sin^2(x))dx陈景润啊华罗庚, ∫(x^3+1)*(1-cos2x)^(1/2)dx ∫[（1+cos2x）^1/2]+[|x|(sinx)^3] dx 求解∫(x+2sinxcosx)／(1+cos2x) dx ∫ln(1+X)／(2-X)²dx ∫X/1+cos2x dx 求下列不定积分.求详解（1）∫[(cos 2x)／(cos x﹢sin x)]dx; (2) ∫cot²xdx; (3) ∫{(1+2x²)／[x²(1+x²)]}dx; (4) ∫sin²(x／2)dx; (5) ∫[(cos2x)／(sin²xcos²x)]dx; (6) ∫[e^(x-4)]dx;求解 2sin^x+1>cos2x+2如何→cos2x 求不定积分∫(cos2x)/(sin^2x)(cos^2x)dx求不定积分,∫(cos2x)/(sin^2x)(cos^2x)dx,∫cos二倍x除以sin平方x 乘cos平方x dx ∫sin^2x/(1+sin^2x )dx求解, ∫(1-sin^2( x/2))dx ∫(cosx／1+sin^2x)dx ∫sin^2x(1+tanx)dx ∫1/sin(x/2)dx