急!y=2sin(2x+∮)(-π
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急!y=2sin(2x+∮)(-π急!y=2sin(2x+∮)(-π急!y=2sin(2x+∮)(-πy=2(sin2xcos∮+cos2xsin∮)=2[sin(-2x)cos∮+cos(-2x)s
急!y=2sin(2x+∮)(-π
急!y=2sin(2x+∮)(-π
急!y=2sin(2x+∮)(-π
y=2(sin2xcos∮+cos2xsin∮)
=2[sin(-2x)cos∮+cos(-2x)sin∮]
则有cos∮=0,
所以∮=-π/2
急!y=2sin(2x+∮)(-π
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