如果虚数z满足z^3=8,则（z^2+2z+5)*(3-2i)=
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如果虚数z满足z^3=8,则（z^2+2z+5)*(3-2i)=如果虚数z满足z^3=8,则（z^2+2z+5)*(3-2i)=如果虚数z满足z^3=8,则（z^2+2z+5)*(3-2i)=z^3-
如果虚数z满足z^3=8,则（z^2+2z+5)*(3-2i)=
如果虚数z满足z^3=8,则（z^2+2z+5)*(3-2i)=
如果虚数z满足z^3=8,则（z^2+2z+5)*(3-2i)=
z^3-8=(z-2)(z^2+2z+4)=0
z是虚数
z-2≠0
所以z^2+2z+4=0
则z^2+2z+5=1
所以原式=3-2i
如果虚数z满足z^3=8,则（z^2+2z+5)*(3-2i)=
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