(x^2)^n+1÷x^2n=?

f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n (-x^2n-2)*(-x)^5÷[x^n+1*x^n*(-x)]=? 已知 x ^3n-2 ÷x^ n+1 =x^3-n×x^n+2,求n的值 (4x^n-2x^n-1-3x^n+2)÷（-5x^n-1) (x^2)^n+1÷x^2n=? x^(n)*x^(n+1)+x^(2n)*x 若(x^2+1/x)^n(n∈N+,n (-x^2n-2)(-x)^5÷[x^n+1·x^n`(-x)] f(X+1)=lim(n-无穷）（n+x)/n-2)n 求f(x) 设集合M={x|x=2n+1,n∈N},N={x|x=3n,n∈N},则M∩N= 因式分解：(x^n+1)+(2x^n)+(x^n-1) x^n+1-2x^n+x^n-1因式分解 x^n-1-2x^n+x^n-1因式分解 分解因式x^n-x^(n-1)+x^(n-2) C语言 f(x)=1+x+x^2/2!+x^3/3!+...+x^n/n!直到|x^n/n| x^n-2x^n+1,因式分解 x^m×(x^n)^3÷[x^(m-1)×2x^(n-1)]= x+x/1=2,x^n+x^n/1=?,n=自然数