3x-y+z=4, 2x+3y-z=12, x+y+z=6
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3x-y+z=4,2x+3y-z=12,x+y+z=63x-y+z=4,2x+3y-z=12,x+y+z=63x-y+z=4,2x+3y-z=12,x+y+z=63x-y+z=4.12x+3y-z=1
3x-y+z=4, 2x+3y-z=12, x+y+z=6
3x-y+z=4, 2x+3y-z=12, x+y+z=6
3x-y+z=4, 2x+3y-z=12, x+y+z=6
3x-y+z=4.1
2x+3y-z=12.2
x+y+z=6 .3
1式+2式得
5x+2y=16.4
2式+3式得
3x+4y=18.5
4式*2-5式
7x=14
x=2
将x=2代入4式得
5*2+2y=16
2y=6
y=3
将x=2,y=3代入3式得
2+3+z=6
z=1
所以x=2,y=3,z=1
x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少,
x+y/2=z+x/3=y+z/4 x+y+z=27
3x-y+z=4,2z+3y-z=12,x+y+z=6的解
x+2y=3x+2z=4y+z 求x:y:z
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
X=3z X+y+z=12 X+2y-2z=10
2x+z=10 x+y-z=4 3x-y-z=0
解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6}
解方程组2x+3y-z=12,3x-y+z=4,x+y+z=6
{3x-y+z=4,2x+3y-z=12,x+y+z=6
3x-y+z=4,2x+3y-z=12,x+y+z=6
3x - y + Z=4{ 2x + 3y - Z=12X + Y + Z = 6
3x-y+z=4, 2x+3y-z=12, x+y+z=6
3x-y+z=4 2x+3y-z=12 x+y+z=6
2x+3y-z=12 3x-y+z=4 x+y+z=6
x-4y+z=-3 2x-y+z=18 x-y-z=12
x：y：z=2:3:4,x+2y-z=12,求x,y,z