求值域的题目y=(x-2)/(x+1) x≠±1

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求值域的题目y=(x-2)/(x+1)x≠±1求值域的题目y=(x-2)/(x+1)x≠±1求值域的题目y=(x-2)/(x+1)x≠±1y=(x+1-3)/(x+1)=(x+1)/(x+1)-3/(

求值域的题目y=(x-2)/(x+1) x≠±1
求值域的题目y=(x-2)/(x+1) x≠±1

求值域的题目y=(x-2)/(x+1) x≠±1
y=(x+1-3)/(x+1)
=(x+1)/(x+1)-3/(x+1)
=1-3/(x+1)
3/(x+1)≠0
所以1-3/(x+1)≠1
x≠1,y≠-1/2
所以值域(-∞,-1/2)∪(-1/2,1)∪(1,+∞)

9x²+4=6x^4+4x²-2
6x^4-5x²-6=0
(2x²-3)(3x²+2)=0
x²=3/2,x²=-2/3(舍去)
所以x=-√6/2,x=√6/2