证明6x^5+11x^4+5x^3+5x^2-x-6能被x^2+1整除?

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/24 13:53:58
证明6x^5+11x^4+5x^3+5x^2-x-6能被x^2+1整除?证明6x^5+11x^4+5x^3+5x^2-x-6能被x^2+1整除?证明6x^5+11x^4+5x^3+5x^2-x-6能被

证明6x^5+11x^4+5x^3+5x^2-x-6能被x^2+1整除?
证明6x^5+11x^4+5x^3+5x^2-x-6能被x^2+1整除?

证明6x^5+11x^4+5x^3+5x^2-x-6能被x^2+1整除?
6x^5+11x^4+5x^3+5x^2-x-6
=(6x^5+6x^4)+(5x^4+5x^3)+(5x^2-x-6)
=6x^4(x+1)+5x^3(x+1)+(5x-6)(x+1)
=(x+1)(6x^4+5x^3+5x-6)
=(x+1)[(6x^4-6)+(5x^3+5x)]
=(x+1)[6(x^2+1)(x^2-1)+5x(x^2+1)]
=(x+1)(x^2+1)(6x^2+5x-6)
因为(x+1)(x^2+1)(6x^2+5x-6)能被(x^2+1)整除,所以原式能被它整除.

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