若sin(π/6+α)=3/5,则cos(α-π/3)=
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若sin(π/6+α)=3/5,则cos(α-π/3)=若sin(π/6+α)=3/5,则cos(α-π/3)=若sin(π/6+α)=3/5,则cos(α-π/3)=解cos(a-π/3)=cos(
若sin(π/6+α)=3/5,则cos(α-π/3)=
若sin(π/6+α)=3/5,则cos(α-π/3)=
若sin(π/6+α)=3/5,则cos(α-π/3)=
解
cos(a-π/3)
=cos(π/3-a)
=cos[π/2-(a+π/6)]
=sin(π/6+a)
=3/5
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