若cos(α+π/6)-sinα=(3√3)/5,则cos(α+π/3)=___

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若cos(α+π/6)-sinα=(3√3)/5,则cos(α+π/3)=___若cos(α+π/6)-sinα=(3√3)/5,则cos(α+π/3)=___若cos(α+π/6)-sinα=(3√

若cos(α+π/6)-sinα=(3√3)/5,则cos(α+π/3)=___
若cos(α+π/6)-sinα=(3√3)/5,则cos(α+π/3)=___

若cos(α+π/6)-sinα=(3√3)/5,则cos(α+π/3)=___
用a吧
cosacosπ/6-sinasinπ/6-sina=3√3/5
cosa*√3/2-sina*1/2-sina=3√3/5
cosa*√3/2-sina*3/2=3√3/5
两边除以√3
cosa*1/2-sina*√3/2=3/5
cosacosπ/3-sinasinπ/3=3/5
所以cos(a+π/3)=3/5

cos(α+π/6)-sinα=(3√3)/5
cosαcosπ/6+0.5sinα=(3√3)/5
cosαcosπ/6+sinαsinπ/6=(3√3)/5
cos(α-π/6)=(3√3)/5
sin(α+π/3)=(3√3)/5
则cos(α+π/3)=(3√3)/2

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