若sin(π/6+α)=3/5,则cos(π/3-α)=?速求哈~
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若sin(π/6+α)=3/5,则cos(π/3-α)=?速求哈~若sin(π/6+α)=3/5,则cos(π/3-α)=?速求哈~若sin(π/6+α)=3/5,则cos(π/3-α)=?速求哈~由
若sin(π/6+α)=3/5,则cos(π/3-α)=?速求哈~
若sin(π/6+α)=3/5,则cos(π/3-α)=?
速求哈~
若sin(π/6+α)=3/5,则cos(π/3-α)=?速求哈~
由题知,
sin(π/6+α)=3/5
所以.
cos(π/3-α)
=cos(π/2-(π/6+α))
=sin(π/6+α)
=3/5
这样可以么?
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