f(x,y,z)=z-x^2-2y^2,则f在(1,1,3)处沿曲面z=X^2+2Y^2在该点处的上侧法线方向的方向导数是__.
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 13:14:36
f(x,y,z)=z-x^2-2y^2,则f在(1,1,3)处沿曲面z=X^2+2Y^2在该点处的上侧法线方向的方向导数是__.f(x,y,z)=z-x^2-2y^2,则f在(1,1,3)处沿曲面z=
f(x,y,z)=z-x^2-2y^2,则f在(1,1,3)处沿曲面z=X^2+2Y^2在该点处的上侧法线方向的方向导数是__.
f(x,y,z)=z-x^2-2y^2,则f在(1,1,3)处沿曲面z=X^2+2Y^2在该点处的上侧法线方向的方向导数是__.
f(x,y,z)=z-x^2-2y^2,则f在(1,1,3)处沿曲面z=X^2+2Y^2在该点处的上侧法线方向的方向导数是__.
z=x^2+2y^2
g(x,y,z)=z-x^2-2y^2
gx(x,y,z)=-2x gy(x,y,z)=-4y gz(x,y,z)=1
代入x=1,y=1
n=(-2,-4,1)
ef/el=ef/ex*(-2)/根号21+ef/ey*(-4)/根号21+ef/ez*1/根号21
=(4x+16y+1)/根号21
代入x=1,y=1
方向导数=根号21
分解因式:f(x,y,z)=x^2(y-z)+y^2(z-x)+z^2(x-y)
f(x,y,z)=(x^2+y^2)^0.5+z^1.5,求 ∂f(x,y,z)/∂y
设z=f(x^2-y^2,e^(xy)),求偏导z/x,偏导z/y
用行列式的性质证明:y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证?
(x-2y+z)(x+y-2z)分之(y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之(x-z)(y-z)=?第三部分那个是 (y+z-2x)(x-2y+z)分之(x-z)(y-z)
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
设f(x,y,z)=e^x*y*z^2,其中z=z(x,y)是由x+y=z+x*e^(z-x-y)确定的隐函数,则f'x(0,1,1)=
设z=f(x^2,y,y/x)可导,求δz/δx,δz/δy
设函数f可微,z=f(ye^x,x/(y^2)) 求z/x,z/y
一道函数不等式题求出所有这样的函数f:R-R,使得对于一切x,y,z∈R,有f(x+y)+f(y+z)+f(x+z)=3f(x+2y+3z)f(x+y)+f(y+z)+f(x+z)=3f(x+2y+3z)改为f(x+y)+f(y+z)+f(x+z)≥3f(x+2y+3z)
高数求梯度设函数f(x,y,z)=(x-y)2+(y-z)2+(z-x)2,求gradf(x,y,z).我算对了吗
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)
计算:(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)
(x+y-z)^2-(x-y+z)^2=?
(x-y-z)*( )=x^2-(y+z)^2 填空