已知x2+2xy-2x+y2-2y+1=0,则x+y等于

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已知x2+2xy-2x+y2-2y+1=0,则x+y等于已知x2+2xy-2x+y2-2y+1=0,则x+y等于已知x2+2xy-2x+y2-2y+1=0,则x+y等于x2+2xy-2x+y2-2y+

已知x2+2xy-2x+y2-2y+1=0,则x+y等于
已知x2+2xy-2x+y2-2y+1=0,则x+y等于

已知x2+2xy-2x+y2-2y+1=0,则x+y等于
x2+2xy-2x+y2-2y+1
=X2+2XY+Y2-2(X+Y)+1
=(X+Y)2-2(X+Y)+1
=(X+Y-1)2=0
X+Y-1=0
X+Y=1

x2+2xy-2x+y2-2y+1=0
（x+y）^2 -2（x+y）+1=0
【（x+y）-1】^2=0
x+y-1 =0
x+y=1

看懂了，给我个满意，没有其他要求！

1
（x+y）²-2（x+y）+1=0
（x+y-1）²=0

x^2+2xy-2x+y^2-2y+1=0
(x+y)^2-2(x+y)+1 =0
(x+y -1)^2=0
x+y =1

1

x2+2xy-2x+y2-2y+1=0
(X^2+2XY+Y^2)-(2X+2Y)+1=0
(X+Y)^2-2(X+Y)+1=0
(X+Y-1)^2=0
X+Y-1=0
X+Y=1

原式=x²+2xy+y²-2x-2y+1=0
（x+y）²-2（x+y）+1=0
[(x+y)-1]²=0
解得：x+y=1

X+Y=1

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