若x²+xy+y²=14,x²-xy+y²=28,求x+y的值
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若x²+xy+y²=14,x²-xy+y²=28,求x+y的值若x²+xy+y²=14,x²-xy+y²=28,求x+y
若x²+xy+y²=14,x²-xy+y²=28,求x+y的值
若x²+xy+y²=14,x²-xy+y²=28,求x+y的值
若x²+xy+y²=14,x²-xy+y²=28,求x+y的值
x²+xy+y²=14,x²-xy+y²=28
相加
2(x²+y²)=42
x²+y²=21
相减
2xy=-14
所以(x+y)²
=x²+2xy+y²
=7
x+y=±√7
若x²+xy-2y²=0,则x²+3xy+y²/x²+y²
若x² +xy+y² =14,x² -xy+y²=28求x+y的值
若x²+xy+y²=14,x²-xy+y²=28,求x+y的值
x²+xy-2y²=0则x²+3xy+y²/x²+y²
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